Three containers have volumes in the ratio 3: | vedclass

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(C) Let the volumes of the three containers be $3x, 4x,$ and $5x$ respectively.In the first container,the amount of milk is $\frac{4}{5} 	imes 3x = \

Vedclass · Accepted Answer

$157:53$

Vedclass · Answer

(C) Let the volumes of the three containers be $3x, 4x,$ and $5x$ respectively.In the first container,the amount of milk is $\frac{4}{5} 	imes 3x = \frac{12x}{5}$ and water is $\frac{1}{5} 	imes 3x = \frac{3x}{5}$.In the second container,the amount of milk is $\frac{3}{4} 	imes 4x = 3x$ and water is $\frac{1}{4} 	imes 4x = x$.In the third container,the amount of milk is $\frac{5}{7} 	imes 5x = \frac{25x}{7}$ and water is $\frac{2}{7} 	imes 5x = \frac{10x}{7}$.Total milk in the fourth container = $\frac{12x}{5} + 3x + \frac{25x}{7} = \frac{84x + 105x + 125x}{35} = \frac{314x}{35}$.Total water in the fourth container = $\frac{3x}{5} + x + \frac{10x}{7} = \frac{21x + 35x + 50x}{35} = \frac{106x}{35}$.The ratio of milk to water is $\frac{314x}{35} : \frac{106x}{35} = 314 : 106 = 157 : 53$.

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