Three equal circles of unit radius touch one another. Then the area of the circle circumscribing the three circles is

  • A
    $6 \pi(2+\sqrt{3})^{2}$
  • B
    $\frac{\pi}{6}(2+\sqrt{3})^{2}$
  • C
    $\frac{\pi}{3}(2+\sqrt{3})^{2}$
  • D
    $3 \pi(2+\sqrt{3})^{2}$

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