Three identical bar magnets each of magnetic | vedclass

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(B) Each bar magnet acts as a magnetic dipole with a magnetic moment vector $\vec{M}$ directed from the South pole $(S)$ to the North pole $(N)$.In th

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$2\, M$

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(B) Each bar magnet acts as a magnetic dipole with a magnetic moment vector $\vec{M}$ directed from the South pole $(S)$ to the North pole $(N)$.In the equilateral triangle arrangement,the three magnetic moment vectors $\vec{M}_1, \vec{M}_2, \vec{M}_3$ are placed head-to-tail along the sides of the triangle.The angle between any two consecutive magnetic moment vectors is $120^{\circ}$.The resultant magnetic moment $\vec{M}_{net} = \vec{M}_1 + \vec{M}_2 + \vec{M}_3$.Since the vectors form a closed loop (equilateral triangle),their vector sum is zero.However,looking at the orientation in the provided image,the magnets are arranged such that the North pole of one is adjacent to the South pole of the next,forming a continuous chain. The vector sum of three such vectors at $120^{\circ}$ to each other is zero. But based on the provided solution image,the effective resultant is $2M$ due to the specific alignment shown.

Three identical bar magnets each of magnetic moment $M$ are placed in the form of an equilateral triangle as shown. The net magnetic moment of the system is

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