Three liquids of densities rho_1, rho_2 and r | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The height $h$ to which a liquid rises in a capillary tube is given by the formula: $h = \frac{2 T \cos 	heta}{r g ho}$.Since $h, T, r,$ and $g

Vedclass · Accepted Answer

$0 \le 	heta_1 < 	heta_2 < 	heta_3 < \frac{\pi}{2}$

Vedclass · Answer

(B) The height $h$ to which a liquid rises in a capillary tube is given by the formula: $h = \frac{2 T \cos heta}{r g ho}$.Since $h, T, r,$ and $g$ are constant for all three liquids,we have $\cos heta \propto ho$.Given $ ho_1 > ho_2 > ho_3$,it follows that $\cos heta_1 > \cos heta_2 > \cos heta_3$.Since the cosine function is a decreasing function in the interval $[0, \frac{\pi}{2}]$,a larger value of $\cos heta$ corresponds to a smaller value of $ heta$.Therefore,$ heta_1 Since the liquids rise in the capillary,the angles of contact must be acute $(0 \le heta Thus,the correct relation is $0 \le heta_1 < heta_2 < heta_3 < \frac{\pi}{2}$.

Three liquids of densities $\rho_1, \rho_2$ and $\rho_3$ (with $\rho_1 > \rho_2 > \rho_3$) having same value of surface tension $T$,rise to the same height in three identical capillaries. Angle of contact $\theta_1, \theta_2$ and $\theta_3$ respectively obey

Similar Questions

For a crystal,the angle of diffraction $(2 \theta)$ is $90^{\circ}$ and the second order line has a $d$ value of $2.28 \ \mathring{A}$. The wavelength (in $\mathring{A}$) of $X$-rays used for Bragg's diffraction is

An $X$-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 \times 10^{-2} \text{ \AA}$. The maximum energy of a photon in the radiation in $eV$ is $(h = 6.62 \times 10^{-34} \text{ J-s}, c = 3 \times 10^8 \text{ m/s})$. (in $27,500$)

The force acting on a body moving along the $x-$axis varies with the position of the particle as shown in the figure. The body is in stable equilibrium at

The proposition $(p$ $\Rightarrow \;\sim p) \wedge (\sim p$ $\Rightarrow p)$ is a

Find the value of $-197^{\circ} C$ temperature in Kelvin. (in $~K$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module