(C) The force exerted by a liquid on the base of a vessel is equal to the weight of the liquid contained in it,provided the vessel has vertical walls

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The force exerted by a liquid on the base of a vessel is equal to the weight of the liquid contained in it,provided the vessel has vertical walls (like a cubical vessel).The force $F$ is given by $F = mg$.Since the masses of the liquids in all three vessels are equal $(m_{A} = m_{B} = m_{C} = m)$,the force exerted on the base of each vessel is $F_{A} = F_{B} = F_{C} = mg$.Therefore,the force exerted by the liquid on the base is the same in all the vessels.

Class 11 Physics Fluid Mechanics and Surface Tension Pressure and Density (of Mixure)

Medium

Three liquids of equal masses are taken in three identical cubical vessels $A$,$B$,and $C$. Their densities are $\rho_{A}$,$\rho_{B}$,and $\rho_{C}$ respectively,where $\rho_{A} < \rho_{B} < \rho_{C}$. The force exerted by the liquid on the base of the cubical vessel is

KCET 2010 All KCET

A
maximum in vessel $C$
B
minimum in vessel $C$
C
the same in all the vessels
D
maximum in vessel $A$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Physics Questions

Chapter

Fluid Mechanics and Surface Tension

Subtopic

Pressure and Density (of Mixure)

Previous Year

KCET 2010 Paper All KCET years →

Why is it difficult to cook on hills?

Medium

View Solution

Fill in the blanks:
$(i)$ $1 \text{ atm} = \dots \text{ Pascal}$
$(ii)$ $1 \text{ torr} = \dots \text{ Pascal}$
$(iii)$ $1 \text{ bar} = \dots \text{ Pa}$
$(iv)$ $1 \text{ atm} = \dots \text{ cm Hg}$

Easy

View Solution

What is thrust?

Medium

View Solution

Two substances of densities ${\rho _1}$ and ${\rho _2}$ are mixed in equal volumes and the relative density of the mixture is $4$. When they are mixed in equal masses,the relative density of the mixture is $3$. The values of ${\rho _1}$ and ${\rho _2}$ are

Medium

View Solution

Three identical vessels are filled to the same height with three different liquids $A, B$ and $C$ $(\rho_A > \rho_B > \rho_C)$. The pressure at the base will be

Easy

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Three liquids of equal masses are taken in three identical cubical vessels $A$,$B$,and $C$. Their densities are $\rho_{A}$,$\rho_{B}$,and $\rho_{C}$ respectively,where $\rho_{A} < \rho_{B} < \rho_{C}$. The force exerted by the liquid on the base of the cubical vessel is

Similar Questions

Why is it difficult to cook on hills?

Fill in the blanks:$(i)$ $1 \text{ atm} = \dots \text{ Pascal}$$(ii)$ $1 \text{ torr} = \dots \text{ Pascal}$$(iii)$ $1 \text{ bar} = \dots \text{ Pa}$$(iv)$ $1 \text{ atm} = \dots \text{ cm Hg}$

What is thrust?

Two substances of densities ${\rho _1}$ and ${\rho _2}$ are mixed in equal volumes and the relative density of the mixture is $4$. When they are mixed in equal masses,the relative density of the mixture is $3$. The values of ${\rho _1}$ and ${\rho _2}$ are

Three identical vessels are filled to the same height with three different liquids $A, B$ and $C$ $(\rho_A > \rho_B > \rho_C)$. The pressure at the base will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Fill in the blanks:
$(i)$ $1 \text{ atm} = \dots \text{ Pascal}$
$(ii)$ $1 \text{ torr} = \dots \text{ Pascal}$
$(iii)$ $1 \text{ bar} = \dots \text{ Pa}$
$(iv)$ $1 \text{ atm} = \dots \text{ cm Hg}$