Three point charges 3 text{ nC},6 text{ nC},a | vedclass

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(D) The potential energy $U$ of a system of point charges is given by the sum of the potential energies of all pairs of charges:$U = \frac{1}{4 \pi \e

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(D) The potential energy $U$ of a system of point charges is given by the sum of the potential energies of all pairs of charges:$U = \frac{1}{4 \pi \epsilon_0} \left( \frac{q_1 q_2}{r_{12}} + \frac{q_2 q_3}{r_{23}} + \frac{q_3 q_1}{r_{31}} ight)$Given $q_1 = 3 	imes 10^{-9} 	ext{ C}$,$q_2 = 6 	imes 10^{-9} 	ext{ C}$,$q_3 = 9 	imes 10^{-9} 	ext{ C}$,and $r = 0.1 	ext{ m}$.$U = \frac{9 	imes 10^9}{0.1} \left( (3 	imes 6) + (6 	imes 9) + (9 	imes 3) ight) 	imes 10^{-18} 	ext{ J}$$U = 9 	imes 10^{11} 	imes (18 + 54 + 27) 	imes 10^{-18} 	ext{ J}$$U = 9 	imes 10^{11} 	imes 99 	imes 10^{-18} 	ext{ J}$$U = 891 	imes 10^{-7} 	ext{ J} = 8.91 	imes 10^{-6} 	ext{ J}$

Three point charges $3 \text{ nC}$,$6 \text{ nC}$,and $9 \text{ nC}$ are placed at the corners of an equilateral triangle of side $0.1 \text{ m}$. The potential energy of the system is:

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