Three point charges are placed at the corners | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a system of point charges to be in equilibrium, the net electrostatic force on each individual charge must be zero.In an equilateral triangle,

Vedclass · Accepted Answer

The system can never be in equilibrium.

Vedclass · Answer

(A) For a system of point charges to be in equilibrium, the net electrostatic force on each individual charge must be zero.In an equilateral triangle, the forces exerted by any two charges on the third charge are directed along the sides of the triangle.Since these forces are vectors acting at $60^{\circ}$ to each other, their resultant can only be zero if the charges are such that the vector sum of forces is zero.However, for three point charges at the vertices of an equilateral triangle, it is mathematically impossible for the net force on all three charges to be zero simultaneously, regardless of the magnitudes or signs of the charges.Therefore, the system can never be in equilibrium under the influence of electrostatic forces alone.

Three point charges are placed at the corners of an equilateral triangle. Assuming only electrostatic forces are acting, which of the following statements is true?

Similar Questions

An oil drop carries six electronic charges,has a mass of $1.6 \times 10^{-12} \text{ g}$ and falls with a terminal velocity in air. The magnitude of the vertical electric field required to make the drop move upward with the same speed as it was formerly moving is ........$kN/C$.

Two equal negative charges $-q$ are placed at points $(0, a)$ and $(0, -a)$ on the $Y$-axis. A positive charge $q$ is released from rest at point $(2a, 0)$. What will be the motion of this charge?

Four charges $2C, -3C, -4C$ and $5C$ respectively are placed at the corners of a square of side length $L$. Which of the following statements is true for the point of intersection of the diagonals?

Two identical particles of mass $m$ carry a charge $Q$ each. Initially, one is at rest on a smooth horizontal plane and the other is projected along the plane directly towards the first particle from a large distance with speed $v$. The closest distance of approach is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module