Three resistances $2 \Omega, 3 \Omega$ and $4 \Omega$ are connected in parallel. The ratio of currents passing through them when a potential difference is applied across its ends will be

Eight copper wires of length $l$ and diameter $d$ are joined in parallel to form a single composite conductor of resistance $R$. If a single copper wire of length $2\,l$ has the same resistance $R$,then its diameter will be $.....d$.

$A$ wire of resistance $R$ and length $L$ is cut into $5$ equal parts. If these parts are joined in parallel,then the resultant resistance will be:

Two resistors are connected $(a)$ in series $(b)$ in parallel. The equivalent resistance in the two cases are $9 \ \Omega$ and $2 \ \Omega$ respectively. Then the resistances of the component resistors are

$A$ conductor of resistance $3 \Omega$ is stretched uniformly until its length is doubled. The wire is now bent in the form of an equilateral triangle. The effective resistance between the ends of any side of the triangle in ohms is

In the figure shown,what is the current (in Ampere) drawn from the battery? You are given $R_1 = 15\,\Omega$,$R_2 = 10\,\Omega$,$R_3 = 20\,\Omega$,$R_4 = 5\,\Omega$,$R_5 = 25\,\Omega$,$R_6 = 30\,\Omega$,and $E = 15\,V$.