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(D) Let the three consecutive odd integers be $x$,$(x+2)$,and $(x+4)$.According to the problem,three times the first integer is $3$ more than twice th

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$15$

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(D) Let the three consecutive odd integers be $x$,$(x+2)$,and $(x+4)$.According to the problem,three times the first integer is $3$ more than twice the third integer.$3x = 2(x+4) + 3$$3x = 2x + 8 + 3$$3x - 2x = 11$$x = 11$The three consecutive odd integers are $11$,$13$,and $15$.The third integer is $x + 4 = 11 + 4 = 15$.

Three times the first of three consecutive odd integers is $3$ more than twice the third. The third integer is

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