Three voltameters containing aqueous solution | vedclass

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(B) According to Faraday's law of electrolysis,the mass deposited is given by $w = \frac{E 	imes I_{eff} 	imes t}{96500}$.Here,$w = 10.8 \ g$,$E_{Ag

Vedclass · Accepted Answer

$0.536$

Vedclass · Answer

(B) According to Faraday's law of electrolysis,the mass deposited is given by $w = \frac{E 	imes I_{eff} 	imes t}{96500}$.Here,$w = 10.8 \ g$,$E_{Ag} = 108 \ g/mol$,$t = 10 \ hours = 36000 \ s$.The current efficiency is $50\%$,so the effective current $I_{eff} = I 	imes 0.5$.Substituting the values: $10.8 = \frac{108 	imes (I 	imes 0.5) 	imes 36000}{96500}$.$10.8 = \frac{108 	imes I 	imes 18000}{96500}$.$I = \frac{10.8 	imes 96500}{108 	imes 18000} = \frac{0.1 	imes 96500}{18000} = \frac{9650}{18000} \approx 0.536 \ A$.

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