(A) For a first order reaction,the half-life period $(t_{1/2})$ is given by the formula: $t_{1/2} = \frac{0.693}{k}$.Given,$t_{1/2} = 60 \ min$.Substi

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(A) For a first order reaction,the half-life period $(t_{1/2})$ is given by the formula: $t_{1/2} = \frac{0.693}{k}$.Given,$t_{1/2} = 60 \ min$.Substituting the value in the formula: $60 = \frac{0.693}{k}$.Therefore,$k = \frac{0.693}{60} \ min^{-1}$.$k = 0.01155 \ min^{-1}$.

Class 12 Chemistry Chemical Kinetics First Order reaction

Easy

Time required to decompose $SO_2Cl_2$ to half of its initial amount is $60 \ min$. If the decomposition is a first order reaction,calculate the rate constant of the reaction. (in $min^{-1}$)

A
$0.01155$
B
$0.0231$
C
$0.00577$
D
$0.0155$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

First Order reaction

If the half-life of a first-order reaction is $6.93$ minutes, then the time required for the completion of $99\%$ of the reaction will be . . . . . . minutes. (Given: $\log 2 = 0.3010$)

DifficultJEE MAIN 2026

View Solution

The unit of the specific reaction rate constant for a first-order reaction (if the concentration is expressed in molarity) is:

Medium

View Solution

If the decomposition reaction $A_{(g)} \longrightarrow B_{(g)}$ follows first-order kinetics,then the graph of the rate of formation of $B$,denoted by $R$,against time $t$ will be:

EasyAP EAMCET 2011

View Solution

For a first-order reaction,the rate constant is $60 \ s^{-1}$. How much time will it take for the initial concentration of the reactant to be reduced to $1/10$th of its initial value?

Difficult

View Solution

For a first-order reaction $A \to B$,the rate of reaction at a reactant concentration of $0.01 \, M$ is $2.0 \times 10^{-5} \, mol \, L^{-1} \, s^{-1}$. The half-life period of the reaction is .... $s$.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Time required to decompose $SO_2Cl_2$ to half of its initial amount is $60 \ min$. If the decomposition is a first order reaction,calculate the rate constant of the reaction. (in $min^{-1}$)

Similar Questions

If the half-life of a first-order reaction is $6.93$ minutes, then the time required for the completion of $99\%$ of the reaction will be . . . . . . minutes. (Given: $\log 2 = 0.3010$)

The unit of the specific reaction rate constant for a first-order reaction (if the concentration is expressed in molarity) is:

If the decomposition reaction $A_{(g)} \longrightarrow B_{(g)}$ follows first-order kinetics,then the graph of the rate of formation of $B$,denoted by $R$,against time $t$ will be:

For a first-order reaction,the rate constant is $60 \ s^{-1}$. How much time will it take for the initial concentration of the reactant to be reduced to $1/10$th of its initial value?

For a first-order reaction $A \to B$,the rate of reaction at a reactant concentration of $0.01 \, M$ is $2.0 \times 10^{-5} \, mol \, L^{-1} \, s^{-1}$. The half-life period of the reaction is .... $s$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module