To a solution of a colourless efflorescent so | vedclass

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(C) The sodium salt is sodium thiosulphate $(Na_2S_2O_3 \cdot 5H_2O)$, which is a colourless efflorescent salt.
When dilute acid is added to it, it u

Vedclass · Accepted Answer

$Na_2S_2O_3$

Vedclass · Answer

(C) The sodium salt is sodium thiosulphate $(Na_2S_2O_3 \cdot 5H_2O)$, which is a colourless efflorescent salt.
When dilute acid is added to it, it undergoes disproportionation to form sulphur (white precipitate) and sulphur dioxide gas $(SO_2)$:
$Na_2S_2O_{3(s)} + 2H^+_{(aq)} ightarrow S_{(s)} + SO_{2(g)} + H_2O_{(\ell)} + 2Na^+_{(aq)}$
$SO_2$ gas turns acidified potassium dichromate solution green due to the reduction of $Cr(VI)$ to $Cr(III)$:
$K_2Cr_2O_{7(	ext{aq})} + 3SO_{2(	ext{g})} + H_2SO_{4(	ext{aq})} ightarrow K_2SO_{4(	ext{aq})} + Cr_2(SO_4)_{3(	ext{aq})} + H_2O_{(\ell)}$
Thus, the correct option is $C$.

Column-$I$	Column-$II$
$P$. $NaBr + \text{Conc. } H_2SO_4 \rightarrow$	$A$. Colourless gas
$Q$. $Na_2S + \text{dil. } HCl \rightarrow$	$B$. Brown colour
$R$. $NaNO_2 + \text{dil. } HCl \rightarrow$	$C$. Rotten egg smell
$S$. $NaNO_3 + \text{Conc. } H_2SO_4 \rightarrow$	$D$. Paramagnetic

To a solution of a colourless efflorescent sodium salt, when dilute acid is added, a colourless gas is evolved along with the formation of a white precipitate. Acidified dichromate solution turns green when the colourless gas is passed through it. The sodium salt is

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