To clear a debt,Ajaybhai has to pay Rs. 100 i | vedclass

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(C) The amounts to be paid by Ajaybhai in monthly instalments are as follows:Amount paid in the $1^{st}$ instalment $= Rs. 100$Amount paid in the $2^{

Vedclass · Accepted Answer

$1250$

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(C) The amounts to be paid by Ajaybhai in monthly instalments are as follows:Amount paid in the $1^{st}$ instalment $= Rs. 100$Amount paid in the $2^{nd}$ instalment $= Rs. 100 + 50 = Rs. 150$Amount paid in the $3^{rd}$ instalment $= Rs. 150 + 50 = Rs. 200$Thus,the amounts (in $Rs.$) to be paid by Ajaybhai form a finite Arithmetic Progression ($A$.$P$.): $100, 150, 200, \dots$ up to $24$ terms.For this $A$.$P$.,the first term $a = 100$ and the common difference $d = 150 - 100 = 50$.To find the amount paid in the $24^{th}$ instalment,we use the formula for the $n^{th}$ term of an $A$.$P$.:$T_n = a + (n - 1)d$For $n = 24$:$T_{24} = a + (24 - 1)d$$T_{24} = 100 + 23(50)$$T_{24} = 100 + 1150$$T_{24} = 1250$Thus,Ajaybhai will pay $Rs. 1250$ in the $24^{th}$ instalment.

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