To draw a histogram to represent the following frequency distribution:

Class interval	$5-10$	$10-15$	$15-25$	$25-45$	$45-75$
Frequency	$6$	$12$	$10$	$8$	$15$

The adjusted frequency for the class $25-45$ is:

The mean of the $10$ observations is $11$. If one new observation is included,their mean becomes $12$. The included new observation is ........

$A$ football player scored the following number of goals in $10$ matches:
$1, 3, 2, 5, 8, 6, 1, 4, 7, 9$
Since the number of matches is $10$ (an even number),the median is calculated as:
Median $= \frac{5^{\text{th}} \text{ observation} + 6^{\text{th}} \text{ observation}}{2}$
$= \frac{8 + 6}{2} = 7$
Is this the correct answer? If not,why?

The information regarding the marks scored by $30$ students in a $50$ marks test is given below:

Marks $(x_{i})$	$15$	$22$	$28$	$31$	$35$	$40$	$44$	$46$
Number of students $(f_{i})$	$2$	$3$	$5$	$6$	$6$	$4$	$3$	$1$

Find the mean of the data.

The mean of $10$ observations is $52$. If $12$ is subtracted from each observation,then the mean of the new observations so obtained is:

Find the mean,the median,and the mode of the observations:
$48, 41, 36, 35, 41, 37, 39, 52, 41, 48$