To get an output Y = 1 in the given circuit,w | vedclass

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(C) The given circuit consists of an $OR$ gate followed by an $AND$ gate. The output of the $OR$ gate is $(A + B)$. This output is then fed into an $A

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$A = 1, B = 0, C = 1$

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(C) The given circuit consists of an $OR$ gate followed by an $AND$ gate. The output of the $OR$ gate is $(A + B)$. This output is then fed into an $AND$ gate along with input $C$. Thus,the final Boolean expression for the output $Y$ is $Y = (A + B) \cdot C$.To get an output $Y = 1$,both inputs to the $AND$ gate must be $1$. This means $(A + B) = 1$ and $C = 1$.For $(A + B) = 1$,at least one of $A$ or $B$ must be $1$. Checking the options:- For option $A$: $A=0, B=1, C=0 \implies Y = (0+1) \cdot 0 = 0$.- For option $B$: $A=1, B=0, C=0 \implies Y = (1+0) \cdot 0 = 0$.- For option $C$: $A=1, B=0, C=1 \implies Y = (1+0) \cdot 1 = 1$.- For option $D$: $A=1, B=1, C=0 \implies Y = (1+1) \cdot 0 = 0$.Thus,the correct input is $A = 1, B = 0, C = 1$.

To get an output $Y = 1$ in the given circuit,which of the following inputs will be correct?

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