To get an output of 1 from the circuit shown | vedclass

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(C) The given circuit consists of an $OR$ gate followed by an $AND$ gate. Let the output of the $OR$ gate be $X = a + b$. The final output of the circ

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$a = 1, b = 0, c = 1$

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(C) The given circuit consists of an $OR$ gate followed by an $AND$ gate. Let the output of the $OR$ gate be $X = a + b$. The final output of the circuit is $Y = X \cdot c = (a + b) \cdot c$.For the output $Y$ to be $1$,both inputs to the $AND$ gate must be $1$. Therefore,$(a + b) = 1$ and $c = 1$.For $(a + b) = 1$,at least one of $a$ or $b$ must be $1$.Checking the options:Option $A$: $a=0, b=0, c=1 \implies Y = (0+0) \cdot 1 = 0 \cdot 1 = 0$.Option $B$: $a=1, b=0, c=0 \implies Y = (1+0) \cdot 0 = 1 \cdot 0 = 0$.Option $C$: $a=1, b=0, c=1 \implies Y = (1+0) \cdot 1 = 1 \cdot 1 = 1$.Option $D$: $a=0, b=1, c=0 \implies Y = (0+1) \cdot 0 = 1 \cdot 0 = 0$.Thus,the correct input is $a=1, b=0, c=1$.

To get an output of $1$ from the circuit shown in the figure,the input must be:

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