Tobacco seed globin forms face-centered cubic | vedclass

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(B) The formula for density is $d = \frac{Z 	imes M}{a^3 	imes N_A}$.Rearranging for molar mass $M$: $M = \frac{d 	imes a^3 	imes N_A}{Z}$.Given:

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$3.6 	imes 10^5 \, g \, mol^{-1}$

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(B) The formula for density is $d = \frac{Z 	imes M}{a^3 	imes N_A}$.Rearranging for molar mass $M$: $M = \frac{d 	imes a^3 	imes N_A}{Z}$.Given: $d = 1.287 \, g \, cm^{-3}$,$a = 12.3 \, nm = 12.3 	imes 10^{-7} \, cm$,$Z = 4$ (for $FCC$),and $N_A = 6.022 	imes 10^{23} \, mol^{-1}$.Substituting the values: $M = \frac{1.287 	imes (12.3 	imes 10^{-7})^3 	imes 6.022 	imes 10^{23}}{4}$.$M = \frac{1.287 	imes 1860.867 	imes 10^{-21} 	imes 6.022 	imes 10^{23}}{4}$.$M \approx 3.6 	imes 10^5 \, g \, mol^{-1}$.

Tobacco seed globin forms face-centered cubic crystals with a unit cell dimension of $12.3 \, nm$ and a density of $1.287 \, g \, cm^{-3}$. Its molecular mass will be:

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