Total number of non-bonded electrons present | vedclass

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Question

(A) The total number of valence electrons in $NO_2^{-}$ is calculated as follows:Valence electrons of $N = 5$Valence electrons of $O = 6 	imes 2 = 12

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) The total number of valence electrons in $NO_2^{-}$ is calculated as follows:Valence electrons of $N = 5$Valence electrons of $O = 6 	imes 2 = 12$Negative charge = $1$Total valence electrons = $5 + 12 + 1 = 18$.In the $NO_2^{-}$ structure,the nitrogen atom is bonded to two oxygen atoms with one single bond and one double bond $(O=N-O^{-})$.Each double bond involves $4$ electrons (bonding) and each single bond involves $2$ electrons (bonding).Total bonding electrons = $4 + 2 = 6$.Total non-bonded (lone pair) electrons = Total valence electrons - Total bonding electrons = $18 - 6 = 18 - 6 = 12$.Thus,the total number of non-bonded electrons is $12$.

Total number of non-bonded electrons present in $NO_2^{-}$ ion based on Lewis theory is $........$

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