The total number of stereoisomers possible fo | vedclass

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(B) The compound is $1,3,5$-tribromocyclohexane. It has three chiral centers at positions $1, 3,$ and $5$. Due to the symmetry of the cyclohexane ring

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$3$

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(B) The compound is $1,3,5$-tribromocyclohexane. It has three chiral centers at positions $1, 3,$ and $5$. Due to the symmetry of the cyclohexane ring,we can have different spatial arrangements of the bromine atoms (cis/trans). The possible stereoisomers are: $1$. All three $Br$ atoms are on the same side (all-cis isomer),which has a plane of symmetry (meso compound). $2$. Two $Br$ atoms are on one side and one $Br$ atom is on the opposite side (cis-cis-trans isomer). This exists as a pair of enantiomers. $3$. One $Br$ atom is on one side and two $Br$ atoms are on the opposite side (trans-trans-cis isomer). This is identical to the previous case due to symmetry. Thus,there are $3$ stereoisomers: one meso form and one pair of enantiomers $(1 + 2 = 3)$.

The total number of stereoisomers possible for the given compound $1,3,5$-tribromocyclohexane is:

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