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(B) The given compound is a $1,2$-disubstituted cyclohexane. $1$. The cyclohexane ring has two chiral centers at positions $1$ and $2$. Since the subs

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$16$

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(B) The given compound is a $1,2$-disubstituted cyclohexane. $1$. The cyclohexane ring has two chiral centers at positions $1$ and $2$. Since the substituents are different,the number of stereoisomers due to the ring is $2^n = 2^2 = 4$ (cis-enantiomers,trans-enantiomers). $2$. The side chain attached at position $2$ is $-	ext{CH}=	ext{CH}-	ext{CH}=	ext{CH}-	ext{CH}_2	ext{CH}_3$. This chain contains two double bonds,both of which can exhibit geometrical isomerism ($E/Z$ or $cis/trans$). $3$. The number of geometrical isomers due to the two double bonds is $2^n = 2^2 = 4$ ($E,E$; $E,Z$; $Z,E$; $Z,Z$). $4$. Since the chiral centers in the ring and the double bonds in the side chain are independent,the total number of stereoisomers is the product of the number of stereoisomers from each part: $4 	imes 4 = 16$.

Total number of stereo-isomers possible for the following compound is:
$1,2$-disubstituted cyclohexane with a $-\text{CH}_2\text{OH}$ group at position $1$ and a $-\text{CH}=\text{CH}-\text{CH}=\text{CH}-\text{CH}_2\text{CH}_3$ group at position $2$.

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Total number of stereo-isomers possible for the following compound is: $1,2$-disubstituted cyclohexane with a $-\text{CH}_2\text{OH}$ group at position $1$ and a $-\text{CH}=\text{CH}-\text{CH}=\text{CH}-\text{CH}_2\text{CH}_3$ group at position $2$.