Transition metals show paramagnetism.
- ADue to characteristic configuration
- BHigh lattice energy
- CDue to variable oxidation states
- DDue to unpaired electrons
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Similar Questions
Match the following:
List-$I$ List-$II$ $A$. Titanium $I$. Non-metal $B$. Fluorine $II$. Transition metal $C$. Tellurium $III$. Lanthanoid $D$. Dysprosium $IV$. Metalloid
| List-$I$ | List-$II$ |
|---|---|
| $A$. Titanium | $I$. Non-metal |
| $B$. Fluorine | $II$. Transition metal |
| $C$. Tellurium | $III$. Lanthanoid |
| $D$. Dysprosium | $IV$. Metalloid |
$A$ first row transition metal in its $+2$ oxidation state has a spin-only magnetic moment value of $3.86 \ BM$. The atomic number of the metal is
Which elements do you think would have been named by
$(i)$ Lawrence Berkeley Laboratory
$(ii)$ Seaborg's group?
$(i)$ Lawrence Berkeley Laboratory
$(ii)$ Seaborg's group?
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View SolutionWhy is $Cr^{2+}$ reducing and $Mn^{3+}$ oxidising when both have $d^{4}$ configuration?
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View SolutionTransition elements are coloured.
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