Twenty-one times a positive number is less th | vedclass

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Question

(A) Let the positive number be $x$.According to the problem,the square of the number exceeds $21$ times the number by $100$.This can be written as the

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) Let the positive number be $x$.According to the problem,the square of the number exceeds $21$ times the number by $100$.This can be written as the equation: $x^2 - 21x = 100$.Rearranging the equation to standard quadratic form: $x^2 - 21x - 100 = 0$.Factoring the quadratic equation: $(x - 25)(x + 4) = 0$.This gives two possible values for $x$: $x = 25$ or $x = -4$.Since the problem specifies a positive number,we discard $x = -4$.Therefore,the value of the positive number is $25$.

Twenty-one times a positive number is less than its square by $100$. The value of the positive number is:

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