Two cm of rain has fallen on a square Km of l | vedclass

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(B) Area of land $= 1 \, Km^2 = (1000 \, m) 	imes (1000 \, m) = 1,000,000 \, m^2$. Height of rainfall $= 2 \, cm = 0.02 \, m$. Total volume of rain $

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$10 \, m$

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(B) Area of land $= 1 \, Km^2 = (1000 \, m) 	imes (1000 \, m) = 1,000,000 \, m^2$. Height of rainfall $= 2 \, cm = 0.02 \, m$. Total volume of rain $= 	ext{Area} 	imes 	ext{Height} = 1,000,000 \, m^2 	imes 0.02 \, m = 20,000 \, m^3$. Volume of water collected in the pool $= 50 \% 	ext{ of } 20,000 \, m^3 = 0.5 	imes 20,000 = 10,000 \, m^3$. Base area of the pool $= 100 \, m 	imes 10 \, m = 1,000 \, m^2$. Increase in water level $= \frac{	ext{Volume collected}}{	ext{Base area}} = \frac{10,000 \, m^3}{1,000 \, m^2} = 10 \, m$.

Two $cm$ of rain has fallen on a square $Km$ of land. Assuming that $50 \%$ of the raindrops could have been collected and contained in a pool having a $100 \, m \times 10 \, m$ base,by what level would the water level in the pool have increased?

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