Two balanced dice are rolled. Find the probab | vedclass

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(C) When two balanced dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.For the product of the numbers on the two dice to be

Vedclass · Accepted Answer

$\frac{1}{4}$

Vedclass · Answer

(C) When two balanced dice are rolled,the total number of possible outcomes is $6 	imes 6 = 36$.For the product of the numbers on the two dice to be odd,both numbers must be odd.The odd numbers on a die are $\{1, 3, 5\}$.Thus,the number of favorable outcomes is $3 	imes 3 = 9$.The favorable outcomes are: $(1,1), (1,3), (1,5), (3,1), (3,3), (3,5), (5,1), (5,3), (5,5)$.The probability $P$ is given by the ratio of favorable outcomes to total outcomes:$P = \frac{9}{36} = \frac{1}{4}$.

Two balanced dice are rolled. Find the probability that the product of numbers on two dice is odd.

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