Two beams of red and violet colours are made | vedclass

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(D) For a prism,the angle of deviation is given by $\delta = (i + e) - A$. In the position of minimum deviation,the angle of incidence is equal to the

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$30^{\circ}$ for both the colours

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(D) For a prism,the angle of deviation is given by $\delta = (i + e) - A$. In the position of minimum deviation,the angle of incidence is equal to the angle of emergence,i.e.,$i = e$. Under this condition,the light ray inside the prism travels parallel to the base,and the angle of refraction $r$ is given by $r_1 = r_2 = r$. Since $A = r_1 + r_2$,we have $A = 2r$. Given the prism angle $A = 60^{\circ}$,the angle of refraction is $r = \frac{A}{2} = \frac{60^{\circ}}{2} = 30^{\circ}$. This condition is independent of the wavelength or colour of the light. Therefore,the angle of refraction is $30^{\circ}$ for both red and violet colours.

Two beams of red and violet colours are made to pass separately through a prism of $A=60^{\circ}$. In the minimum deviation position,the angle of refraction inside the prism will be

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