(B) The force of kinetic friction acting on a block is given by $f_k = \mu_k N = \mu_k mg$. For block $A$: Mass $m_A = 2 \ kg$,Force $F = 20 \ N$. Fri

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(B) The force of kinetic friction acting on a block is given by $f_k = \mu_k N = \mu_k mg$. For block $A$: Mass $m_A = 2 \ kg$,Force $F = 20 \ N$. Friction $f_A = 0.3 \times 2 \times 10 = 6 \ N$. Net force $F_{net,A} = F - f_A = 20 - 6 = 14 \ N$. Acceleration $a_A = F_{net,A} / m_A = 14 / 2 = 7 \ m \ s^{-2}$. For block $B$: Mass $m_B = 4 \ kg$,Force $F = 20 \ N$. Friction $f_B = 0.3 \times 4 \times 10 = 12 \ N$. Net force $F_{net,B} = F - f_B = 20 - 12 = 8 \ N$. Acceleration $a_B = F_{net,B} / m_B = 8 / 4 = 2 \ m \ s^{-2}$. The ratio of accelerations is $a_A : a_B = 7 : 2$.

Class 11 Physics Newton's Laws of Motion and Friction Kinetic Friction and Motion on Rough Horizontal Surface

Medium

Two blocks $A$ and $B$ of masses $2 \ kg$ and $4 \ kg$ respectively are kept on a rough horizontal surface. If the same force of $20 \ N$ is applied on each block,then the ratio of the accelerations of the blocks $A$ and $B$ is (Coefficient of kinetic friction between the surface and the blocks is $0.3$ and acceleration due to gravity $= 10 \ m \ s^{-2}$).

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A
$1: 1$
B
$7: 2$
C
$1: 2$
D
$4: 3$

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Class 11

Physics Questions

Chapter

Newton's Laws of Motion and Friction

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Kinetic Friction and Motion on Rough Horizontal Surface

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