Two blocks each of mass $M$ are resting on a frictionless inclined plane as shown in the figure. Then:

As per the given figure,a weightless pulley $P$ is attached on a double inclined frictionless surface. The tension in the string (massless) will be (if $g = 10 \, m/s^2$):

$A$ frictionless wire $AB$ is fixed on a circle of radius $R$. $A$ very small bead slips on this wire. The time taken by the bead to slip from $A$ to $B$ is:

For the system shown in the figure,if $M_1 = 10 \ kg$,$M_2 = 5 \ kg$,$\theta = 30^\circ$,and $g = 10 \ m/s^2$,find the tension in the string in $N$.

$A$ small block slides without friction down an inclined plane starting from rest. Let $S_n$ be the distance travelled from time $t = n - 1$ to $t = n$. Then $\frac{S_n}{S_{n+1}}$ is

Block $A$ of weight $100 \, N$ rests on a frictionless inclined plane of slope angle $30^{\circ}$. $A$ flexible cord attached to $A$ passes over a frictionless pulley and is connected to block $B$ of weight $w$. Find the weight $w$ for which the system is in equilibrium.