Two bodies of equal masses move with the unif | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let the mass of each body be $m$. The kinetic energy $(KE)$ of the first body is given by $K_{1} = \frac{1}{2}mv^{2} \quad \dots(i)$. The kinetic

Vedclass · Accepted Answer

$9:1$

Vedclass · Answer

(D) Let the mass of each body be $m$. The kinetic energy $(KE)$ of the first body is given by $K_{1} = \frac{1}{2}mv^{2} \quad \dots(i)$. The kinetic energy $(KE)$ of the second body is given by $K_{2} = \frac{1}{2}m(3v)^{2} = \frac{1}{2}m(9v^{2}) = \frac{9}{2}mv^{2} \quad \dots(ii)$. To find the ratio of their kinetic energies,we divide equation $(ii)$ by equation $(i)$: $\frac{K_{2}}{K_{1}} = \frac{\frac{9}{2}mv^{2}}{\frac{1}{2}mv^{2}} = \frac{9}{1}$. Thus,the ratio of their kinetic energies is $9:1$.

Two bodies of equal masses move with the uniform velocities $v$ and $3v$ respectively. Find the ratio of their kinetic energies.

Similar Questions

$A$ porter moving vertically upstairs with a load on his head does work. Why?

What is the work done by a coolie walking on a horizontal platform with a load on his head?

State whether the following statement is true or false:
When velocity is halved,its kinetic energy becomes $\frac{1}{4}^{th}$ of its original value.

The velocity of a body moving in a straight line is increased by applying a constant force $F$ for some distance in the direction of the motion. Prove that the increase in the kinetic energy of the body is equal to the work done by the force on the body.

Vedclass Test Series

Exam Paper Generator

Online Exam Module