Two brothers $X$ and $Y$ appeared for an exam. Let $A$ be the event that $X$ has passed the exam and $B$ is the event that $Y$ has passed. The probability of $A$ is $\frac{1}{7}$ and of $B$ is $\frac{2}{9}$. Then,the probability that both of them pass the exam is
- A$\frac{1}{63}$
- B$\frac{2}{35}$
- C$\frac{2}{63}$
- D$\frac{9}{14}$
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