Two bulbs $A$ and $B$ are rated as $90 \, W - 120 \, V$ and $60 \, W - 120 \, V$ respectively. They are connected in parallel across a $120 \, V$ source. Find the current in each bulb. Which bulb will consume more energy?

(A) $(i)$ For bulb $A$:
Resistance,$R_{A} = \frac{V^{2}}{P_{A}} = \frac{(120)^{2}}{90} = 160 \, \Omega$.
Therefore,current $I_{A} = \frac{V}{R_{A}} = \frac{120}{160} = 0.75 \, A$.
For bulb $B$:
Resistance,$R_{B} = \frac{V^{2}}{P_{B}} = \frac{(120)^{2}}{60} = 240 \, \Omega$.
Therefore,current $I_{B} = \frac{V}{R_{B}} = \frac{120}{240} = 0.5 \, A$.
$(ii)$ Since the bulbs are connected in parallel to a $120 \, V$ source,each bulb operates at its rated voltage. Bulb $A$ has a higher power rating $(90 \, W)$ compared to bulb $B$ $(60 \, W)$,therefore bulb $A$ will consume more energy.