Two bulbs,one of 200 V, 60 W and the other | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The resistance of a bulb is given by $R = \frac{V^2}{P}$.For the first bulb $(P_1 = 60 \ W, V = 200 \ V)$:$R_1 = \frac{200^2}{60} = \frac{40000}{6

Vedclass · Accepted Answer

$37.5$

Vedclass · Answer

(A) The resistance of a bulb is given by $R = \frac{V^2}{P}$.For the first bulb $(P_1 = 60 \ W, V = 200 \ V)$:$R_1 = \frac{200^2}{60} = \frac{40000}{60} = \frac{2000}{3} \ \Omega$.For the second bulb $(P_2 = 100 \ W, V = 200 \ V)$:$R_2 = \frac{200^2}{100} = \frac{40000}{100} = 400 \ \Omega$.When connected in series,the total resistance is $R_{eq} = R_1 + R_2 = \frac{2000}{3} + 400 = \frac{2000 + 1200}{3} = \frac{3200}{3} \ \Omega$.The power consumed by the series combination connected to a $200 \ V$ supply is:$P_{total} = \frac{V^2}{R_{eq}} = \frac{200^2}{3200/3} = \frac{40000 	imes 3}{3200} = \frac{400 	imes 3}{32} = \frac{1200}{32} = 37.5 \ W$.

Two bulbs,one of $200 \ V, 60 \ W$ and the other of $200 \ V, 100 \ W$,are connected in series to a $200 \ V$ supply. The power consumed will be ................ $W$.

Similar Questions

Find out the equivalent resistance between $A$ and $B$.

An electric kettle has two coils. When one of these is switched on,the water in the kettle boils in $6\,min$. When the other coil is switched on,the water boils in $3\,min$. If the two coils are connected in series,the time taken to boil the water in the kettle is ............. $min$.

All resistances in the figure are $1\,\Omega$ each. The value of current '$I$' is $\frac{a}{5}\,A$. The value of $a$ is

What is the equivalent resistance between $A$ and $B$?

Three conductors draw currents of $1 \,A, 2 \,A$ and $3 \,A$ respectively, when connected in turn across a battery. If they are connected in series and the combination is connected across the same battery, the current drawn will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module