Two buses A and B are moving in opposite dire | vedclass

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(C) The given situation is as shown in the figure.Velocity of bus $A$, $v_A = 36 \ km/h = 36 	imes \frac{5}{18} = 10 \ m/s$ (towards east).Velocity o

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moving with a speed of $15 \ m/s$ from east to west

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(C) The given situation is as shown in the figure.Velocity of bus $A$, $v_A = 36 \ km/h = 36 	imes \frac{5}{18} = 10 \ m/s$ (towards east).Velocity of bus $B$, $v_B = 18 \ km/h = 18 	imes \frac{5}{18} = 5 \ m/s$ (towards west).Let the direction towards the east be positive. Then, $v_A = +10 \ m/s$ and $v_B = -5 \ m/s$.The relative velocity of bus $B$ with respect to bus $A$ is given by:$v_{BA} = v_B - v_A = (-5) - (10) = -15 \ m/s$.The negative sign indicates that the bus $B$ appears to move towards the west relative to bus $A$.Therefore, bus $B$ appears to bus $A$ as moving with a speed of $15 \ m/s$ from east to west.

Two buses $A$ and $B$ are moving in opposite directions. If the first bus $A$ moves towards the east with a speed of $36 \ km/h$ and bus $B$ moves towards the west with a speed of $18 \ km/h$, then the bus $B$ appears to bus $A$ as:

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