Two capacitors C_1 and C_2 are charged to 120 | vedclass

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(D) When two capacitors are connected such that their potential becomes zero,it implies that the total charge on the plates connected together must be

Vedclass · Accepted Answer

$3C_1 = 5C_2$

Vedclass · Answer

(D) When two capacitors are connected such that their potential becomes zero,it implies that the total charge on the plates connected together must be zero.Let the charges on the capacitors be $Q_1 = C_1 V_1$ and $Q_2 = C_2 V_2$.For the potential to become zero upon connection,the charges must be equal in magnitude and opposite in sign,such that $Q_1 + Q_2 = 0$,which means $C_1 V_1 = C_2 V_2$.Given $V_1 = 120\, V$ and $V_2 = 200\, V$,we have:$120 C_1 = 200 C_2$Dividing both sides by $40$:$3 C_1 = 5 C_2$

Two capacitors $C_1$ and $C_2$ are charged to $120\, V$ and $200\, V$ respectively. It is found that by connecting them together,the potential on each one can be made zero. Then:

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