Two capacitors C_1 and C_2 are connected in p | vedclass

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(D) Since the capacitors are connected in parallel to the same battery,the potential difference $V$ across both capacitors is the same.From the charge

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$C_2 > C_1, U_2 > U_1$

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(D) Since the capacitors are connected in parallel to the same battery,the potential difference $V$ across both capacitors is the same.From the charge-time graph,we observe the maximum charge $q$ stored on the capacitors. As $t 	o \infty$,the charge on the capacitor reaches its maximum value $q = CV$.From the graph,it is clear that the steady-state charge $q_2$ for capacitor $C_2$ is greater than the steady-state charge $q_1$ for capacitor $C_1$ (i.e.,$q_2 > q_1$).Since $q = CV$ and $V$ is constant,$q \propto C$. Therefore,$C_2 > C_1$.The energy stored in a capacitor is given by $U = \frac{1}{2} CV^2 = \frac{q^2}{2C}$. Alternatively,using $U = \frac{1}{2} qV$,since $V$ is constant and $q_2 > q_1$,it follows that $U_2 > U_1$.Thus,$C_2 > C_1$ and $U_2 > U_1$.

Two capacitors $C_1$ and $C_2$ are connected in parallel to a battery. The charge-time graph is shown below for the two capacitors. The energy stored in them is $U_1$ and $U_2$,respectively. Which of the given statements is true?

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