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(B) Given: Capacitance of each capacitor $C = 2 	imes 10^{-6} \ F$.Breakdown voltage of each capacitor $V = 5000 \ V$.When capacitors are connected i

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$10^{-6} \ F$ and $10000 \ V$

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(B) Given: Capacitance of each capacitor $C = 2 	imes 10^{-6} \ F$.Breakdown voltage of each capacitor $V = 5000 \ V$.When capacitors are connected in series,the equivalent capacitance $C_S$ is given by:$\frac{1}{C_S} = \frac{1}{C} + \frac{1}{C} = \frac{2}{C}$$C_S = \frac{C}{2} = \frac{2 	imes 10^{-6}}{2} = 10^{-6} \ F$.When capacitors are connected in series,the total breakdown voltage of the combination is the sum of the individual breakdown voltages:$V_S = V + V = 5000 \ V + 5000 \ V = 10000 \ V$.

Two capacitors each having a capacitance $2 \times 10^{-6} \ F$ and a breakdown voltage $5000 \ V$,are joined in series. What will be the resultant capacitance and the breakdown voltage of the combination?

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