Two cards are drawn at random one after the o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total number of cards is $52$. The number of ace cards is $4$. Since the cards are drawn with replacement, the probability of drawing an ace i

Vedclass · Accepted Answer

$\frac{2}{13}$

Vedclass · Answer

(B) The total number of cards is $52$. The number of ace cards is $4$. Since the cards are drawn with replacement, the probability of drawing an ace in a single trial is $p = \frac{4}{52} = \frac{1}{13}$. The probability of not drawing an ace is $q = 1 - p = \frac{12}{13}$.This is a binomial distribution $B(n, p)$ where $n = 2$ and $p = \frac{1}{13}$.The mean of a binomial distribution is given by $E(X) = np$.Mean $= 2 	imes \frac{1}{13} = \frac{2}{13}$.

Two cards are drawn at random one after the other with replacement from a pack of playing cards. If $X$ is the random variable denoting the number of ace cards drawn, then the mean of the probability distribution of $X$ is

Similar Questions

$A$ fair coin is tossed $100$ times. The probability of getting tails an odd number of times is

Let a biased coin be tossed $5$ times. If the probability of getting $4$ heads is equal to the probability of getting $5$ heads,then the probability of getting at most two heads is

If the mean and variance of a binomial variate $X$ are $8$ and $4$ respectively,then $P(X < 3)$ equals to

For a binomial distribution with mean $6$ and variance $2$,find $P(X \geq 2)$.

$A$ bag contains $2$ white and $4$ black balls. $A$ ball is drawn $5$ times with replacement. The probability that at least $4$ of the balls drawn are white is

Vedclass Test Series

Exam Paper Generator

Online Exam Module