(B) Let the cars $A$ and $B$ meet after time $t$ seconds. At the point of meeting,the distance traveled by both cars must be equal.For car $A$ moving

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(B) Let the cars $A$ and $B$ meet after time $t$ seconds. At the point of meeting,the distance traveled by both cars must be equal.For car $A$ moving with uniform velocity: $S_A = v_A \times t = 40t$.For car $B$ starting from rest with constant acceleration: $S_B = u_B t + \frac{1}{2} a_B t^2 = 0 + \frac{1}{2} \times 4 \times t^2 = 2t^2$.Since $S_A = S_B$,we have $40t = 2t^2$.Dividing both sides by $2t$ (assuming $t \neq 0$),we get $t = 20\, s$.

Class 11 Physics Motion in Straight Line Uniformly Accelerated Motion

Medium

Two cars $A$ and $B$ are initially at rest at the same point. If car $A$ starts with a uniform velocity of $40\, m/s$ and car $B$ starts in the same direction with a constant acceleration of $4\, m/s^2$,then after how much time will car $B$ catch car $A$?

A
$10$
B
$20$
C
$30$
D
$35$

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Motion in Straight Line

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Uniformly Accelerated Motion

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Two cars $A$ and $B$ are initially at rest at the same point. If car $A$ starts with a uniform velocity of $40\, m/s$ and car $B$ starts in the same direction with a constant acceleration of $4\, m/s^2$,then after how much time will car $B$ catch car $A$?

Similar Questions

$A$ lift performs the first part of its ascent with uniform acceleration $a$ and the remaining with uniform retardation $2a$. If $t$ is the total time of ascent,find the total height of the shaft.

An automobile travelling with a speed of $60\,km/h$ can brake to stop within a distance of $20\,m$. If the car is going twice as fast,i.e.,$120\,km/h$,the stopping distance will be ........... $m$.

The displacement of a particle starting from rest at $t=0$ is given by $s=9 t^2-2 t^3$. The time in seconds at which the particle will attain zero velocity is (in $s$)

$A$ particle is moving along the $X$-axis with velocity $v = e^{-\beta x}$. At time $t = 0$,the particle is located at $x = 0$. The displacement of the particle as a function of time is

If a body loses half of its velocity on penetrating $3 \, cm$ in a wooden block,then how much will it penetrate more before coming to rest? (in $cm$)

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