Two cities are 150, km apart. Electric power | vedclass

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(B) The distance between the two cities is $d = 150\, km$.The total resistance of the copper wire is $R = (0.5\, \Omega/km) 	imes (150\, km) = 75\, \

Vedclass · Accepted Answer

$19.2\, kW$

Vedclass · Answer

(B) The distance between the two cities is $d = 150\, km$.The total resistance of the copper wire is $R = (0.5\, \Omega/km) 	imes (150\, km) = 75\, \Omega$.The total voltage drop across the wire is $V = (8\, V/km) 	imes (150\, km) = 1200\, V$.The power loss in the wire is given by the formula $P = \frac{V^2}{R}$.Substituting the values,$P = \frac{(1200\, V)^2}{75\, \Omega} = \frac{1440000}{75}\, W = 19200\, W$.Converting to kilowatts,$P = 19.2\, kW$.

Two cities are $150\, km$ apart. Electric power is sent from one city to another city through copper wires. The fall of potential per $km$ is $8\, V$ and the average resistance per $km$ is $0.5\, \Omega$. The power loss in the wire is

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