Two coaxial solenoids of different radii carry current $I$ in the same direction. Let $\overrightarrow{F_1}$ be the magnetic force on the inner solenoid due to the outer one and $\overrightarrow{F_2}$ be the magnetic force on the outer solenoid due to the inner one. Then

  • A
    $\overrightarrow{F_1}$ is radially inwards and $\overrightarrow{F_2}$ is radially outwards
  • B
    $\overrightarrow{F_1}$ is radially inwards and $\overrightarrow{F_2} = 0$
  • C
    $\overrightarrow{F_1}$ is radially outwards and $\overrightarrow{F_2} = 0$
  • D
    $\overrightarrow{F_1} = \overrightarrow{F_2} = 0$

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Consider a circular current-carrying loop of radius $R$ in the $x-y$ plane with its centre at the origin. Consider the line integral $\Im(L) = \left| \int_{-L}^{L} \vec{B} \cdot d\vec{l} \right|$ taken along the $z$-axis.
$(a)$ Show that $\Im(L)$ monotonically increases with $L$.
$(b)$ Use an appropriate Amperian loop to show that $\Im(\infty) = \mu_0 I$,where $I$ is the current in the wire.
$(c)$ Verify this result directly.
$(d)$ Suppose we replace the circular coil with a square coil of side $R$ carrying the same current $I$. What can you say about $\Im(L)$ and $\Im(\infty)$?

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