Two coherent monochromatic light beams of int | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The maximum intensity in an interference pattern is given by $I_{\max} = (\sqrt{I_1} + \sqrt{I_2})^2$.Substituting the given values,$I_{\max} = (\

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(C) The maximum intensity in an interference pattern is given by $I_{\max} = (\sqrt{I_1} + \sqrt{I_2})^2$.Substituting the given values,$I_{\max} = (\sqrt{4I} + \sqrt{9I})^2 = (2\sqrt{I} + 3\sqrt{I})^2 = (5\sqrt{I})^2 = 25I$.The minimum intensity in an interference pattern is given by $I_{\min} = (\sqrt{I_1} - \sqrt{I_2})^2$.Substituting the given values,$I_{\min} = (\sqrt{4I} - \sqrt{9I})^2 = (2\sqrt{I} - 3\sqrt{I})^2 = (-\sqrt{I})^2 = I$.The difference between the maximum and minimum intensities is $I_{\max} - I_{\min} = 25I - I = 24I$.Comparing this with $xI$,we get $x = 24$.

Two coherent monochromatic light beams of intensities $4 I$ and $9I$ are superimposed. The difference between the maximum and minimum intensities in the resulting interference pattern is $xI$. The value of $x$ is . . . . . . .

Similar Questions

$n$ identical waves each of intensity $I_0$ interfere with each other. The ratio of maximum intensities if the interference is $(i)$ coherent and $(ii)$ incoherent is:

Two coherent sources must have .......

Two coherent sources of light interfere. The intensity ratio of two sources is $1:4$. For this interference pattern,if the value of $\frac{I_{\max} + I_{\min}}{I_{\max} - I_{\min}}$ is equal to $\frac{2\alpha + 1}{\beta + 3}$,then the value of $\frac{\alpha}{\beta}$ will be:

Which phenomena can be explained by the wave nature of light?

Intensities of the two waves of light are $I$ and $4I$. The maximum intensity of the resultant wave after superposition is (in $I$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module