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(C) Given the ratio of intensities of two coherent sources is $\frac{I_1}{I_2} = \frac{9}{4}$.Let $I_1 = 9k$ and $I_2 = 4k$,where $k$ is a constant.Th

Vedclass · Accepted Answer

$25:1$

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(C) Given the ratio of intensities of two coherent sources is $\frac{I_1}{I_2} = \frac{9}{4}$.Let $I_1 = 9k$ and $I_2 = 4k$,where $k$ is a constant.The ratio of maximum intensity to minimum intensity in an interference pattern is given by the formula:$\frac{I_{\max}}{I_{\min}} = \left(\frac{\sqrt{I_1} + \sqrt{I_2}}{\sqrt{I_1} - \sqrt{I_2}}\right)^2$Substituting the values:$\frac{I_{\max}}{I_{\min}} = \left(\frac{\sqrt{9k} + \sqrt{4k}}{\sqrt{9k} - \sqrt{4k}}\right)^2$$\frac{I_{\max}}{I_{\min}} = \left(\frac{3\sqrt{k} + 2\sqrt{k}}{3\sqrt{k} - 2\sqrt{k}}\right)^2$$\frac{I_{\max}}{I_{\min}} = \left(\frac{5\sqrt{k}}{\sqrt{k}}\right)^2 = (5)^2 = 25$Thus,the ratio is $25:1$.

Two coherent sources of intensity ratio $9:4$ produce interference. The intensity ratio of maxima and minima of the interference pattern is

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