Two coherent sources produce waves of differe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The ratio of maximum intensity to minimum intensity is given by: $\frac{I_{max}}{I_{min}} = \left( \frac{\sqrt{I_1} + \sqrt{I_2}}{\sqrt{I_1} - \sq

Vedclass · Accepted Answer

$25 : 9$

Vedclass · Answer

(B) The ratio of maximum intensity to minimum intensity is given by: $\frac{I_{max}}{I_{min}} = \left( \frac{\sqrt{I_1} + \sqrt{I_2}}{\sqrt{I_1} - \sqrt{I_2}} \right)^2 = 16$. Taking the square root on both sides: $\frac{\sqrt{I_1} + \sqrt{I_2}}{\sqrt{I_1} - \sqrt{I_2}} = 4$. Cross-multiplying gives: $\sqrt{I_1} + \sqrt{I_2} = 4\sqrt{I_1} - 4\sqrt{I_2}$. Rearranging the terms: $5\sqrt{I_2} = 3\sqrt{I_1}$. Squaring both sides: $25I_2 = 9I_1$. Therefore,the ratio of intensities is $\frac{I_1}{I_2} = \frac{25}{9}$.

Two coherent sources produce waves of different intensities which interfere. After interference,the ratio of the maximum intensity to the minimum intensity is $16$. The ratio of the intensities of the waves is:

Similar Questions

Two sources are said to be coherent if they produce waves

The energy in the phenomenon of interference

Two light waves with amplitudes in the ratio $3 : 1$ produce interference. The ratio of the maximum to minimum intensity is

Two light waves of intensities $I$ and $4I$ superpose at a point with a phase difference of $\pi / 2$. Calculate the resultant amplitude at that point.

Two coherent sources must have .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module