Two compounds A and B with the same molecular | vedclass

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Question

(C) is propanal $(CH_{3}CH_{2}CHO)$. Reaction with $CH_{3}MgBr$ gives butan$-2-$ol $(CH_{3}CH_{2}CH(OH)CH_{3})$ as $C$.Butan$-2-$ol is a $2^{\circ}$ a

Vedclass · Accepted Answer

$C = CH_{3}CH_{2}CH(OH)CH_{3}$,$D = CH_{3}C(CH_{3})(OH)CH_{3}$

Vedclass · Answer

(C) is propanal $(CH_{3}CH_{2}CHO)$. Reaction with $CH_{3}MgBr$ gives butan$-2-$ol $(CH_{3}CH_{2}CH(OH)CH_{3})$ as $C$.Butan$-2-$ol is a $2^{\circ}$ alcohol,gives positive Iodoform test,and Lucas test turbidity in $5$ minutes.$B$ is acetone $(CH_{3}COCH_{3})$. Reaction with $CH_{3}MgBr$ gives $2$-methylpropan$-2-$ol $(CH_{3}C(CH_{3})(OH)CH_{3})$ as $D$.$2$-methylpropan$-2-$ol is a $3^{\circ}$ alcohol,gives immediate turbidity with Lucas reagent,and negative Iodoform test.Thus,$C$ is $CH_{3}CH_{2}CH(OH)CH_{3}$ and $D$ is $CH_{3}C(CH_{3})(OH)CH_{3}$.

Test	$C$	$D$
Ceric ammonium nitrate Test	Positive	Positive
Lucas Test	Turbidity obtained after five minutes	Turbidity obtained immediately
Iodoform Test	Positive	Negative

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