(B) The magnetic field at the centre of a circular coil is given by $B = \frac{\mu_0 N i}{2r}$.Since the two coils carry currents in opposite directio

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(B) The magnetic field at the centre of a circular coil is given by $B = \frac{\mu_0 N i}{2r}$.Since the two coils carry currents in opposite directions, the net magnetic field at the centre will be the difference between the two fields.Given: $N = 10$, $i_1 = 0.2 \ A$, $r_1 = 0.2 \ m$, $i_2 = 0.3 \ A$, $r_2 = 0.4 \ m$.$B_{\text{net}} = |B_1 - B_2| = \frac{\mu_0 N}{2} |\frac{i_1}{r_1} - \frac{i_2}{r_2}|$$B_{\text{net}} = \frac{10 \mu_0}{2} |\frac{0.2}{0.2} - \frac{0.3}{0.4}|$$B_{\text{net}} = 5 \mu_0 |1 - 0.75|$$B_{\text{net}} = 5 \mu_0 \times 0.25 = \frac{5}{4} \mu_0$.

Class 12 Physics Moving Charges and Magnetism Biot-Savart's Law and its application

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Two concentric coils of $10$ turns each are placed in the same plane. Their radii are $20 \ cm$ and $40 \ cm$ and carry $0.2 \ A$ and $0.3 \ A$ current respectively in opposite directions. The magnetic induction (in $T$) at the centre is

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A
$\frac{3}{4} \mu_0$
B
$\frac{5}{4} \mu_0$
C
$\frac{7}{4} \mu_0$
D
$\frac{9}{4} \mu_0$

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Moving Charges and Magnetism

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Biot-Savart's Law and its application

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Two concentric coils of $10$ turns each are placed in the same plane. Their radii are $20 \ cm$ and $40 \ cm$ and carry $0.2 \ A$ and $0.3 \ A$ current respectively in opposite directions. The magnetic induction (in $T$) at the centre is

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$A$ circular current-carrying coil has radius $R$. At what distance from the centre of the coil on the axis,the magnetic induction will become $\frac{1}{8}$ th of its value at the centre of the coil?

$A$ coil having $100$ turns is wound tightly in the form of a spiral with inner and outer radii $1 \text{ cm}$ and $2 \text{ cm}$, respectively. When a current $1 \text{ A}$ passes through the coil, the magnetic field at the centre of the coil is

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