Two capacitors C_1 and C_2 in a circuit are j | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Since the capacitors $C_1$ and $C_2$ are connected in series,the charge $Q$ on both capacitors must be the same.Let $V_D$ be the potential at poin

Vedclass · Accepted Answer

$\frac{C_1V_1 + C_2V_2}{C_1 + C_2}$

Vedclass · Answer

(C) Since the capacitors $C_1$ and $C_2$ are connected in series,the charge $Q$ on both capacitors must be the same.Let $V_D$ be the potential at point $D$.The charge on capacitor $C_1$ is $Q = C_1(V_A - V_D) = C_1(V_1 - V_D)$.The charge on capacitor $C_2$ is $Q = C_2(V_D - V_B) = C_2(V_D - V_2)$.Equating the charges: $C_1(V_1 - V_D) = C_2(V_D - V_2)$.Expanding the terms: $C_1V_1 - C_1V_D = C_2V_D - C_2V_2$.Rearranging to solve for $V_D$: $C_1V_1 + C_2V_2 = V_D(C_1 + C_2)$.Therefore,$V_D = \frac{C_1V_1 + C_2V_2}{C_1 + C_2}$.

Two capacitors $C_1$ and $C_2$ in a circuit are joined as shown in the figure. The potential of point $A$ is $V_1$ and that of $B$ is $V_2$. The potential of point $D$ will be

Similar Questions

The common name of $Benzene-1,2-diol$ is

The structure which prevents the entry of food into the respiratory tract is

Which of the following is $NOT$ a characteristic of angiosperms?

The centre of mass of two masses $m$ and $m'$ moves by a distance $\frac{x}{5}$ when mass $m$ is moved by a distance $x$ and $m'$ is kept fixed. The ratio $\frac{m'}{m}$ is

If both the mass and the radius of the earth decrease by $1\%$,the value of the acceleration due to gravity will

Vedclass Test Series

Exam Paper Generator

Online Exam Module