Two conducting spheres of radii 9 ,cm and 1 , | vedclass

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(B) The potential $V$ of a conducting sphere of radius $R$ with charge $q$ is given by $V = \frac{1}{4\pi\epsilon_0} \frac{q}{R}$.Given $V = 10 \,V$,

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$\frac{10^{-9}}{4} \,N$

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(B) The potential $V$ of a conducting sphere of radius $R$ with charge $q$ is given by $V = \frac{1}{4\pi\epsilon_0} \frac{q}{R}$.Given $V = 10 \,V$, $R_1 = 0.09 \,m$, and $R_2 = 0.01 \,m$.The charges on the spheres are $q_1 = 4\pi\epsilon_0 R_1 V$ and $q_2 = 4\pi\epsilon_0 R_2 V$.Substituting the values, $q_1 = \frac{0.09 	imes 10}{9 	imes 10^9} = 10^{-10} \,C$ and $q_2 = \frac{0.01 	imes 10}{9 	imes 10^9} = \frac{1}{9} 	imes 10^{-10} \,C$.The distance between the centers is $d = 0.2 \,m$.The force of repulsion is $F = \frac{1}{4\pi\epsilon_0} \frac{q_1 q_2}{d^2} = (9 	imes 10^9) 	imes \frac{10^{-10} 	imes (1/9) 	imes 10^{-10}}{(0.2)^2}$.$F = \frac{10^{-11}}{0.04} = \frac{10^{-11}}{4 	imes 10^{-2}} = 0.25 	imes 10^{-9} \,N = \frac{10^{-9}}{4} \,N$.

Two conducting spheres of radii $9 \,cm$ and $1 \,cm$ are separated by a distance of $20 \,cm$ in free space. If the spheres are charged to the same potential of $10 \,V$ each, the force of repulsion between them is

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