Two copper vessels $A$ and $B$ have the same base area but different shapes. Vessel $A$ requires twice the volume of water as vessel $B$ to fill up to a particular common height. Which of the following statements is correct?

  • A
    Pressure on the base area of vessels $A$ and $B$ is the same.
  • B
    Pressure on the base area of vessels $A$ and $B$ is not the same.
  • C
    Both vessels $A$ and $B$ weigh the same.
  • D
    Vessel $B$ weighs twice that of $A$.

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Similar Questions

Describe the Torricelli experiment for the measurement of atmospheric pressure.

From the adjacent figure,the correct observation is:

$A$ manometer reads the pressure of a gas in an enclosure as shown in Figure $(a)$. When a pump removes some of the gas,the manometer reads as in Figure $(b)$. The liquid used in the manometers is mercury and the atmospheric pressure is $76 \; cm$ of mercury.
$(a)$ Give the absolute and gauge pressure of the gas in the enclosure for cases $(a)$ and $(b)$,in units of $cm$ of mercury.
$(b)$ How would the levels change in case $(b)$ if $13.6 \; cm$ of water (immiscible with mercury) are poured into the right limb of the manometer? (Ignore the small change in the volume of the gas).

On what factors does the pressure at any place depend? Explain.

In a cylindrical container open to the atmosphere from the top,a liquid is filled up to a $10\, m$ depth. The density of the liquid varies with depth $h$ from the surface as $\rho(h) = 100 + 6h^2$,where $h$ is in meters and $\rho$ is in $kg/m^3$. The pressure at the bottom of the container will be: (Atmospheric pressure $P_0 = 10^5\, Pa$,$g = 10\, m/s^2$)

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