Two dice are thrown simultaneously 500 times. | vedclass

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Question

(B) The total number of trials is $500$.Let $E$ be the event that the sum of the two numbers appearing on the uppermost faces of the two dice is less

Vedclass · Accepted Answer

$0.282$

Vedclass · Answer

(B) The total number of trials is $500$.Let $E$ be the event that the sum of the two numbers appearing on the uppermost faces of the two dice is less than or equal to $5$.This includes the sums $2, 3, 4,$ and $5$.The number of times the event $E$ occurred is the sum of the frequencies of these outcomes:Number of trials for $E = 14 + 30 + 42 + 55 = 141$.The probability $P(E)$ is given by the formula:$P(E) = \frac{	ext{Number of trials in which the event happened}}{	ext{Total number of trials}}$$P(E) = \frac{141}{500} = 0.282$.

Sum	Frequency
$2$	$14$
$3$	$30$
$4$	$42$
$5$	$55$
$6$	$72$
$7$	$75$
$8$	$70$
$9$	$53$
$10$	$46$
$11$	$28$
$12$	$15$

Outcome	$1$	$2$	$3$	$4$	$5$	$6$
Frequency	$180$	$150$	$160$	$170$	$150$	$190$

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