Two different conductors have the same resist | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $R_0$ be the resistance of both conductors at $0\,^{\circ}C.$The resistance of the first conductor at $t_1\,^{\circ}C$ is given by $R_1 = R_0(

Vedclass · Accepted Answer

$\frac{t_2}{t_1}$

Vedclass · Answer

(D) Let $R_0$ be the resistance of both conductors at $0\,^{\circ}C.$The resistance of the first conductor at $t_1\,^{\circ}C$ is given by $R_1 = R_0(1 + \alpha_1 t_1).$The resistance of the second conductor at $t_2\,^{\circ}C$ is given by $R_2 = R_0(1 + \alpha_2 t_2).$Given that $R_1 = R_2,$ we have:$R_0(1 + \alpha_1 t_1) = R_0(1 + \alpha_2 t_2)$Dividing both sides by $R_0$:$1 + \alpha_1 t_1 = 1 + \alpha_2 t_2$Subtracting $1$ from both sides:$\alpha_1 t_1 = \alpha_2 t_2$Therefore,the ratio of the temperature coefficients is:$\frac{\alpha_1}{\alpha_2} = \frac{t_2}{t_1}$

Similar Questions

Why are alloys used for making standard resistance coils?

$A$ negligibly small current is passed through a wire of length $15 \ m$ and uniform cross-section $6 \times 10^{-7} \ m^2$,and its resistance is measured to be $5 \ \Omega$. The resistivity of the material at the temperature of the experiment is . . . . . . $\Omega \ m$.

An aluminium wire is stretched to make its length $0.4 \%$ larger. Then the percentage change in resistance is $.....\,\%$.

The length of the wire is doubled. Its conductance will be

What is the resistance of a wire of length $5 \, m$ and resistivity $1.7 \times 10^{-8} \, \Omega \cdot m$,given the cross-sectional area is a hollow cylinder with outer radius $r_2 = 10 \, cm$ and thickness $5 \, mm$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module