Two forces $F_{1} = 20 \, N$ and $F_{2} = 30 \, N$ are acting on an object in opposite directions as shown in the figure.
$(i)$ What is the net force acting on the object?
$(ii)$ What is the direction of the net force acting on the object?
$(iii)$ If the mass of the body is $10 \, kg$,what will be the acceleration produced in it?

(N/A) $(i)$ The net force $F_{net}$ is the difference between the two opposing forces:
$F_{net} = F_{2} - F_{1} = 30 \, N - 20 \, N = 10 \, N$.
$(ii)$ Since $F_{2} > F_{1}$,the net force acts in the direction of the larger force,which is the direction of $F_{2}$ (towards the left).
$(iii)$ According to Newton's second law of motion,$F = ma$,where $m = 10 \, kg$ and $F = 10 \, N$:
$a = F / m = 10 \, N / 10 \, kg = 1 \, m \, s^{-2}$.